MySQL查询7天内过生日的用户 查询生日是今天的用户 解决跨年问题

MySQL查询生日是今天的用户

select * from customer where MONTH(birthday) = MONTH(NOW()) and DAY(birthday) = DAY(NOW())

查询7天内生日的用户(这个不能跨年查询)

select * from customer
where DATE_FORMAT(birthday,'%m-%d') >= DATE_FORMAT(now(),'%m-%d')
and DATE_FORMAT(birthday,'%m-%d') <= DATE_FORMAT(date_add(now(), INTERVAL 6 DAY),'%m-%d')

补充:

解决跨年问题

select user_id , name , birth , user_type from sys_user
where birth >= DATE_FORMAT(now(),'%Y-%m-%d')
and birth <= DATE_FORMAT(date_add(now() , INTERVAL 6 DAY),'%Y-%m-%d')

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